Answer
$v=2.05\times 10^7 \frac{m}{s}$
Work Step by Step
We know that
$K.E=\frac{1}{2}mv^2$
We re-arrange this equation to solve for $v$:
$v^2=\frac{2K.E}{m}$
Taking square root on both sides, we obtain
$v=\sqrt{\frac{2K.E}{m}}$
We know that $1 eV=1.6\times 10^{-19}J$
Therefore, we plug in the know values to obtain:
$v=\sqrt{\frac{2(1.20\times 10^3\times 1.6\times 10^{-19})}{9.109\times 10^{-31}}}$
$v=2.05\times 10^7 \frac{m}{s}$
