Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 830: 27b

Answer

The current is $~~22.7~mA$

Work Step by Step

We can find the number of ions per hour: $\frac{100\times 10^{-6}~kg}{3.92\times 10^{-25}~kg} = 2.55\times 10^{20}$ We can find the current: $i = \frac{(2.55\times 10^{20})(3.20\times 10^{-19}~C)}{3600~s}$ $i = 22.7~mA$ The current is $~~22.7~mA$.
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