Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 830: 25b

Answer

$R=96.4cm$

Work Step by Step

The radius can be determined from the formula: $R=\frac{mv}{qB}$.....................................eq(1) We also know that $K.E=\frac{1}{2}mv^2$ which can be re-arranged as $v=\sqrt{\frac{2K.E}{m}}$ Now, we substitute the values into this formula to find $v$: $v=\sqrt{\frac{2(100\times 1.6\times 10^{-19})}{9.109\times 10^{-31}}}=5.9271\times 10^6\frac{m}{s}$ We then plug in the known values in eq(1) to obtain $R$: $R=\frac{(9.109\times 10^{-31})(5.9271\times 10^6)}{(1.6\times 10^{-19})(35\times10^{-6})}$ $R=0.964m$ or $R=96.4cm$
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