Answer
$F_B=6.2\times 10^{-18}N$
Work Step by Step
We can find the magnetic force using the formula:
$F_B=qvBsin{\theta}$
We plug in the known values to obtain:
$F_B=3.2\times 10^{-19}\times 550\times 0.045\times sin52^{\circ}$
$F_B=6.2\times 10^{-18}N$
