Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 829: 2

Answer

$B = (-0.061~T)~\hat{k}$

Work Step by Step

The upward force on the particle due to the magnetic field must be equal in magnitude to the downward force due to gravity. We can find the magnitude of $B$: $qvB = mg$ $B = \frac{mg}{qv}$ $B = \frac{(0.010~kg)(9.8~m/s^2)}{(80\times 10^{-6}~C)(20\times 10^3~m/s)}$ $B = 0.061~T$ The velocity of the particle is in the +x direction and the force on the particle due to the magnetic field is in the +y direction. By the right hand rule, the direction of the magnetic field is into the page, which is the -z direction. $B = (-0.061~T)~\hat{k}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.