Answer
$v=400 \frac{Km}{s}$
Work Step by Step
The magnetic Force is given as:
$F=qvbsin{\theta}$
the above formula can be rearranged as:
$v=\frac{F}{qbsin{\theta}}$
We now plug in the known values to obtain the value of $v$:
$v=\frac{6.5\times10^{-17}}{1.6\times10^{-19}(2.6\times10^{-3})sin23^{\circ}}$
$v=399.891\times10^3$
After rounding it off, we obtain:
$v=400 \frac{Km}{s}$
