Answer
The potential difference is $~~94~mV$
Work Step by Step
We can find the resistance:
$R = \frac{\rho~L}{A}$
$R = \frac{\rho~L}{\pi~r^2}$
$R = \frac{(3.5\times 10^{-5}~\Omega\cdot m)(2.0\times 10^{-2}~m)}{(\pi)(5.0\times 10^{-3}~m)^2}$
$R = 8.9\times 10^{-3}~\Omega$
We can find the current:
$P = i^2~R$
$i^2 = \frac{P}{R}$
$i = \sqrt{\frac{P}{R}}$
$i = \sqrt{\frac{1.0~W}{8.9\times 10^{-3}~\Omega}}$
$i = 10.6~A$
We can find the potential difference:
$V = i~R$
$V = (10.6~A)(8.9\times 10^{-3}~\Omega)$
$V = 94\times 10^{-3}~V$
$V = 94~mV$
The potential difference is $~~94~mV$
