Answer
$$\ 0.27 $$
Work Step by Step
Recalling that a joule per second is a watt, we obtain $\ (1.3 W)(0.20 s) = 0.27 J$ for the energy that can be transferred at the exit of the pipe.
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 26 - Current and Resistance - Problems - Page 769: 60e
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