Answer
$i = 1.7\times 10^{-5}~A$
Work Step by Step
We can find the current:
$i = \rho~v~A$
$i = \rho~v~\pi~R^2$
$i = (1.1\times 10^{-3}~C/m^3)~(2.0~m/s)~(\pi)~(0.050~m)^2$
$i = 1.7\times 10^{-5}~A$
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