Answer
$R = 5.16\times 10^{-8}~\Omega$
Work Step by Step
We can find the resistivity:
$R = \frac{\rho~L}{A}$
$\rho = \frac{R~A}{L}$
$\rho = \frac{R~\pi~r^2}{L}$
$\rho = \frac{(1.09\times 10^{-3}~\Omega)~(\pi)~(2.75\times 10^{-3}~m)^2}{1.60~m}$
$\rho = 1.62\times 10^{-8}~\Omega\cdot m$
We can find the resistance of the disk:
$R = \frac{\rho~L}{A}$
$R = \frac{\rho~L}{\pi~r^2}$
$R = \frac{(1.62\times 10^{-8}~\Omega\cdot m)~(1.00\times 10^{-3}~m)}{(\pi)~(1.00\times 10^{-2}~m)^2}$
$R = 5.16\times 10^{-8}~\Omega$
