Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 26 - Current and Resistance - Problems - Page 769: 63

Answer

$2.284$ $kW$

Work Step by Step

The formula for resistance of a wire is $\frac{\rho l}{A}$. Changing $l$ from 80 to 70 makes $P = \frac{V^2}{R}$ become $\frac{8}{7}$ of its initial value, or $2.284$ $kW$
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