Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 743: 60a

Answer

$U = (4.9 \times 10^{-3}) J $

Work Step by Step

As, $U = \frac{1}{2} C V^{2}$ $U = \frac{1}{2} (200 \times 10^{-12}) (7 \times 10^{3})^{2}$ $U = (4.9 \times 10^{-3}) J $
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