Answer
$E=10K\frac{V}{m}$
Work Step by Step
We can calculate Electric Field as
$E=\frac{q}{\epsilon_{\circ}{A}}$
Substituting the values, we get
$E=\frac{11\times10^{-9}}{8.85\times10^{-12}(0.12)}$
$E=10.35\times10^3=10K\frac{V}{m}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 743: 53e
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