Answer
$q=1.15nC.$
Work Step by Step
$
\text { } q=C V\\=\left(13.4 \times 10^{-12} \mathrm{~F}\right)(85.5 \mathrm{~V})\\=1.15 \mathrm{nC} \text {. }
$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 743: 52b
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