Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 743: 51b

Answer

$q=5nC$

Work Step by Step

We know that $q=CV$ We plug in the known values to obtain: $q=(100\times10^{-12})(50)$ $q=5\times10^{-9}C$ $q=5nC$
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