Answer
$ q' = 7.7 \times 10^{-7} C$
Work Step by Step
The charge induced is $q' = q (1- \frac{1}{k}) = (8.9 \times 10^{-7}) (1-\frac{1}{7.2}) $
$ q' = 7.7 \times 10^{-7} C$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 743: 54b
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