Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 680: 23a

Answer

$q=0.32\mu C$

Work Step by Step

We know that; $q=\sigma A=\sigma \pi Dh$ $\implies q=\pi \epsilon_{\circ}EDh$ We plug in the known values to obtain: $q=3.1416(8.85\times 10^{-12})(2.3\times 10^5)(0.12)(0.42)=3.2\times 10^{-7}=0.32\times 10^{-6}=0.32\mu C$
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