Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 680: 17a

Answer

$q=37\mu$C

Work Step by Step

We know that $q=4\pi r^2{\sigma}$ Putting the values, we get $q=4\pi(\frac{1.2}{2})^2(8.1\times10^{-6})$ $q=3.7\times10^{-5}=37\times10^{-1}\times10^{-5}=37\times10^{-6}$ $q=37\mu$C
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