Answer
$\sigma=4.1\times10^6\frac{Nm^2}C{}$
Work Step by Step
The electric flux can be calculated as
$\sigma=\frac{q}{\epsilon_{\circ}}$
Putting the values, we get
$\sigma=\frac{3.7\times10^{-5}}{8.85\times10^{-12}}$
$\sigma=4.1\times10^6\frac{Nm^2}C{}$
