Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 680: 22

Answer

$a=2.1\times 10^{17}\frac{m}{s^2}$

Work Step by Step

We know that: $ma=eE=\frac{e\lambda}{2\pi \epsilon{\circ}r}$ This can be rearranged as: $a=\frac{e\lambda}{2\pi \epsilon{\circ}rm}$ We plug in the known values to obtain: $a=\frac{1.6\times 10^{-19}\times6.0\times 10^{-6}}{2(3.1416)\times 8.85\times 10^{-12}\times 0.090\times 9\times 10^{-31}}=2.1\times 10^{17}\frac{m}{s^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.