Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 680: 15b

Answer

$\Phi = \frac{1}{24}~\frac{q}{\epsilon} = 0.0417~\frac{q}{\epsilon}$

Work Step by Step

We can use Gauss' law to find the electric flux through the cube: $\epsilon_0~\Phi = q_{enc}$ $\Phi = \frac{q_{enc}}{\epsilon_0}$ Note that this flux only passes through three faces of the cube. By symmetry, the flux through each of these three faces is $\Phi = \frac{q_{enc}}{3\epsilon_0}$ We could place eight cubes so that a corner of each cube met at the point charge $+q$. Then the charge enclosed by each cube would be $q_{enc} = \frac{+q}{8}$ We can find an expression for the electric flux through each of the other three cube faces: $\Phi = \frac{q_{enc}}{3\epsilon_0}$ $\Phi = \frac{q/8}{3\epsilon_0}$ $\Phi = \frac{1}{24}~\frac{q}{\epsilon_0} = 0.0417~\frac{q}{\epsilon_0}$
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