Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 680: 20b

Answer

The net charge of shell A is $~~1.15\times 10^{-5}~C$

Work Step by Step

The flux is $-9.0\times 10^5~N~m^2/C$ when the enclosed charge within the Gaussian sphere is only the charge of the particle. The flux is $4.0\times 10^5~N~m^2/C$ when the enclosed charge within the Gaussian sphere is the charge of the particle and the charge on shell A. Therefore, the additional flux from shell A is $~~13\times 10^5~N~m^2/C$ We can find the net charge of shell A: $\Phi = \frac{q}{\epsilon_0}$ $q = \Phi ~\epsilon_0$ $q = (13\times 10^5~N~m^2/C)(8.854\times 10^{-12}~F/m)$ $q = 1.15\times 10^{-5}~C$ The net charge of shell A is $~~1.15\times 10^{-5}~C$
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