Answer
$\Delta t=11.63\times10^4 s$
Work Step by Step
As current is the rate of flow of charge, we know:
$i=\frac{\Delta q}{\Delta t}$
This simplifies to:
$\Delta t=\frac{\Delta q}{i}$ .......eq(1)
We know that:
$\Delta q=ne$ where $n=6.023\times10^{23}$ and $e=1.602\times10^{-19}C$
so
$\Delta q=6.023\times10^{23}\times1.602\times10^{-19}=9.65\times10^4 C$
Putting the values into equation(1):
$\Delta t=\frac{9.65\times10^4}{0.83}=11.63\times10^4 s$
