Answer
$\phi = 208^o$
Work Step by Step
We use trigonometry formula to find the angle of the net force
$\phi = tan^{-1} (\frac{F_{4.y \space net}}{F_{4.x \space net}})$
$\phi = tan^{-1} (\frac{-2.89 \times 10^{-24} N}{-5.44 \times 10^{-24} N})$
$\phi = 28^o$
Measured from the +x axis counterclockwise,
$\phi = 180^o + 28^o$
$\phi = 208^o$
