Answer
$ a =7.7 \times 10^{28} m/s^2$
Work Step by Step
Mass of Helium
$m_{He} = (4)(1.67 \times 10^{-27} kg)$
$m_{He} = 6.68 \times 10^{-27} kg$
According to Newton's Second Law,
$F = ma$ and $a = \frac{F}{a} $
Taking from (a), $F = 5.1 \times 10^2 N $
$a = \frac{F}{a} $
$a = \frac{5.1 \times 10^2 N}{6.68 \times 10^{-27} kg} $
$ a =7.7 \times 10^{28} m/s^2$
