Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 582: 95

Answer

$\gamma=1.40$

Work Step by Step

From ideal gas law, the speed of sound is given as; $v_s=\sqrt\frac{\gamma RT}{M}$ This can be rearranged as: $\gamma=\frac{Mv_s^2}{RT}$........eq(1) Next, we find the wavelength: $\lambda =2(9.57cm)=19.14cm=0.1914m$ As $v_s=f\lambda$, $v_s=(1000)(0.1914)=191.5\frac{m}{s}$ Finally, we plug in known values in eq(1) we to obtain: $\gamma=\frac{0.127(191.4)}{8.314(400)}=1.40$
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