Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 582: 84b

Answer

$T_2=365K$

Work Step by Step

For state 2, the ideal gas equation can be written as $P_2V_2=nRT_2$ The above equation can be rewritten as: $T_2=\frac{P_2V_2}{nR}$...............................eq(1) Given that, $P_2=1.5$ $P_1=1.5(20.2\times10^5)=30.3\times10^5Pa$ and $V_2=2V_1=2(0.0015)=0.003m^3$ Putting these values in eq(1) and solving: $T_2=\frac{(30.3\times10^5)(0.003)}{(3)(8.314)}$ $T_2=365K$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.