Answer
$T_1=122K$
Work Step by Step
According to the ideal gas equation,
$PV=nRT$
For state 1, the formula becomes:
$P_1V_1=nRT_1$
We re-arrange this equation to make $T_1$ the subject of the formula:
$T_1=\frac{P_1V_1}{nR}$............................eq(1)
We also know that:
$P_1=20(1.01\times10^5)Pa$
$V_1=1500cm^3=0.0015m^3$
Putting the values of $n,R,P_1,V_1$ in eq(1), we get
$T_1=\frac{(20.2\times10^5)(0.0015)}{(3)(8.314)}$
$T_1=122K$