Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 582: 84a

Answer

$T_1=122K$

Work Step by Step

According to the ideal gas equation, $PV=nRT$ For state 1, the formula becomes: $P_1V_1=nRT_1$ We re-arrange this equation to make $T_1$ the subject of the formula: $T_1=\frac{P_1V_1}{nR}$............................eq(1) We also know that: $P_1=20(1.01\times10^5)Pa$ $V_1=1500cm^3=0.0015m^3$ Putting the values of $n,R,P_1,V_1$ in eq(1), we get $T_1=\frac{(20.2\times10^5)(0.0015)}{(3)(8.314)}$ $T_1=122K$
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