Answer
$P_f=8$ atm
Work Step by Step
As we know that
$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$
$P_2=\frac{P_1V_1}{T_1}\times\frac{T_2}{V_2}$
$V_1=1L=1\times10^{-3}m^3$,$V_2=4L=4\times10^{-3}m^3$ and given that the temperature is isothermal so $T_1=T_2=300K$
Putting these values in the equation and solving:
$P_2=\frac{32(1\times10^{-3})}{300}\times\frac{300}
{4\times10^{-3}}$
$P_2=8$ atm
Therefore, the final temperature is $8$ atm.
