Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 582: 92

Answer

$\gamma=1.40$

Work Step by Step

As we know that $\gamma=\frac{\rho V^2}{P}$ We plug in the known values to obtain: $\gamma=\frac{1.29(331)^2}{1.01\times 10^5}=1.40$
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