Answer
$T_f=120K$
Work Step by Step
We know that
$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$
We re-arrange the above equation into the form below:
$T_2=\frac{P_2V_2}{P_1 V_1}\times T_1$
We know the values of $P_1,P_2,V_1,V_2$ and $T_1$ into the formula and solve:
$T_2=\frac{(3.2)(4\times10^{-3})}{(32)(1\times10^{-3})}\times 300$
$T_2=120K$
Thus $T_2$ or $T_f=120K$
