Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 581: 72

Answer

$T=580K$

Work Step by Step

We know that $v_{rms}=\sqrt\frac{3RT}{M}$ According to given condition, $\sqrt\frac{3RT}{M_{He}}=\sqrt\frac{3RT}{M_H}$ For hydrogen, $T=C^{\circ}+273=20+273=293K$ Therefore, $\sqrt\frac{3RT}{M_{He}}=\sqrt\frac{3R(293)}{M_H}$ Squaring both sides, $\frac{3RT}{M_{He}}=\frac{3R(293)}{M_H}$ $T=\frac{(293)\times M_{He}}{M_H}$ Using Table 19-1 to substitute the values of molar mass in the equation, $T=\frac{(293)\times4}{2.02}=580K$ $T=580K$
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