Answer
$W_{23}=1.81KJ$
Work Step by Step
We know that;
$\Delta E_{int23}=Q_{23}-W_{23}$
Rearranging the above equation:
$W_{23}=Q_{23}-\Delta E_{int23}$
We plug in the known values to obtain:
$W_{23}=0-(-1807.425)=1807.42=1.81\times 10^3=1.81KJ$
