Answer
$P_2=2.00atm$
Work Step by Step
We know that;
$P_2=\frac{nRT_2}{V_2}$
We plug in the known values to obtain:
$P_2=\frac{(1)(8.31)(600)}{0.0246}=202682.93Pa$
As $1.01\times 10^5Pa=1 atm$,
$202682.93Pa=2.00atm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 19 - The Kinetic Theory of Gases - Problems - Page 581: 63n
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