Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 581: 71a

Answer

$W=-374J$

Work Step by Step

From the first law of thermodynamics; $W=Q-\Delta E_{int}$ As $\Delta E_{int}=nCV \Delta T$ so $W=Q-nCV \Delta T$ As $Q=0$; $W=0-nCV \Delta T=-nCV \Delta T$ We know that $C_V=\frac{3}{2}R$. Therefore, $W=-n(\frac{3}{2}R) \Delta T$ We plug in the known values to obtain: $W=-2.0(\frac{3}{2})(8.31)(15.0)=-374J$
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