Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 581: 63o

Answer

$V_3=0.0373m^3$

Work Step by Step

We know that; $V_3=\frac{nRT_3}{P_3}$ We plug in the known values to obtain: $V_3=\frac{(1)(8.31)(455)}{101300}=0.0373m^3$
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