Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 581: 63m

Answer

$V_1=0.0246m^3$

Work Step by Step

We know that; $P_1V_1=nRT$ This can be rearranged as: $V_1=\frac{nRT}{P_1}$ We plug in the known values to obtain: $V_1=\frac{(1)(8.31)(300)}{101300}$ $V_1=0.0246m^3=V_2$ The volume is constant from 1 to 2.
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