Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 407: 9b

Answer

The blood pressure at the feet is $~~1.7\times 10^3~torr$

Work Step by Step

We can find the blood pressure difference between the head and the feet: $\Delta P = \rho g \Delta h$ $\Delta P = (1.06\times 10^3~kg/m^3)(9.8~m/s^2)(21~m)$ $\Delta P = 2.1815\times 10^5~N/m^2$ $\Delta P = (2.1815\times 10^5~N/m^2)(\frac{7.50\times 10^{-3}~torr}{1~Pa})$ $\Delta P = 1636~torr$ We can find the blood pressure at the feet: $p_g = 80~torr+1636~torr$ $p_g = 1.7\times 10^3~torr$ The blood pressure at the feet is $~~1.7\times 10^3~torr$
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