Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 407: 8

Answer

$\Delta P=-\rho _{2}gh-\rho _{1}gh=-\left( 0.87\times 10\times 7.6\times 10^{3}\right) -10^{3}\times 10\times 20=-266120Pa$

Work Step by Step

$$\Delta P=-\rho _{2}gh-\rho _{1}gh=-\left( 0.87\times 10\times 7.6\times 10^{3}\right) -10^{3}\times 10\times 20=-266120Pa$$
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