Answer
The blood pressure at the feet is $~~4.1\times 10^2~torr$
Work Step by Step
We can find the blood pressure difference between the feet and the heart:
$\Delta P = \rho g \Delta h$
$\Delta P = (1.06\times 10^3~kg/m^3)(9.8~m/s^2)(2.0)$
$\Delta P = 2.078\times 10^4~N/m^2$
$\Delta P = (2.078\times 10^4~N/m^2)(\frac{7.50\times 10^{-3}~torr}{1~Pa})$
$\Delta P = 156~torr$
We can find the blood pressure at the feet:
$p_g = 250~torr+156~torr$
$p_g = 4.1\times 10^2~torr$
The blood pressure at the feet is $~~4.1\times 10^2~torr$
