Answer
$F = 2.6\times 10^4~N$
Work Step by Step
We can find the required force:
$F = \pi~R^2~\Delta p$
$F = (\pi)~(0.30~m)^2~(1.00~atm-0.10~atm)$
$F = (\pi)~(0.30~m)^2~(0.90~atm)$
$F = (\pi)~(0.30~m)^2~[(0.90~atm)~(\frac{1.01\times 10^5~N/m^2}{1~atm})]$
$F = 2.6\times 10^4~N$
