Answer
Hydrostatic pressure $=1.08\times10^{3}$ $atm$
Work Step by Step
Hydrostatic pressure at height $h$ below the surface of a liquid with density $\rho$ is given by:
$Hydrostatic$ $pressure=\rho g h$
Substituting the known values and solving the equation gives:
$Hydrostatic$ $pressure=1024$ $kg/m^{3}\times9.8$ $m/s^{2}\times (10.9\times10^{3}$ $m)$
$Hydrostatic$ $pressure\approx1.093\times10^{8}$ $Pa$
$Hydrostatic$ $pressure$ (in atmospheres) $ \approx \frac{1.093\times10^{8}Pa}{1atm}\approx \frac{1.093\times10^{8}Pa}{1.01\times10^{5}} \approx 1083$ $atm$
[as $ 1$ $atm=1.01\times10^{5}Pa$]
Therefore;
$Hydrostatic$ $pressure\approx 1.08\times10^{3}$ $atm$
