Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 407: 12

Answer

$\Delta d_{\max }=0.51-0.34=0.17m$

Work Step by Step

$$\Delta P=\rho g\Delta h\Rightarrow \Delta h=\dfrac {\Delta P}{\rho g}=\dfrac {0.05\times 10^{5}}{1.5\times 10^{3}\times 9.8}\dfrac {0.05\times 10^{5}}{1.5\times 10^{3}\times 9.8}\approx 0.34 ( for Dead Sea)$$ $$\Delta P=\rho g\Delta h\Rightarrow \Delta h=\dfrac {\Delta P}{\rho g}=\dfrac {0.05\times 10^{5}}{1\times 10^{3}\times 9.8}\approx 0.51( for Normal Water)$$ So the d max difference is $$\Delta d_{\max }=0.51-0.34=0.17m$$
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