Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 381: 43b

Answer

$87.5\ min$

Work Step by Step

We know that velocity $v=\frac{Distance }{time}$. In this case, distance is the circumference of the circle i,e $2\pi R$. Therefore, the formula for velocity becomes: $v = \frac{2\pi R}{T}$ Another formula for linear velocity is $v = \sqrt \frac{GM_e}{r}$ Equating above formulas, we can get: $\frac{2\pi R}{T}= \sqrt \frac{GM_e}{r}$ $\frac{T}{2\pi R}=\sqrt \frac{r}{GM_e}$ $T =2\pi\sqrt \frac{r^3}{GM_e}$ $T =2\pi\sqrt \frac{(6.37\times 10^{6}+0.16\times 10^{6})^3}{(6.67\times 10^{-11})(5.98\times 10^{24})}$ $T = 5249.719\ sec$ $T =\frac{5249.719}{60}=87.5\ min$
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