Answer
$K = 2.0\times 10^9~J$
Work Step by Step
On the graph, we can see that at $r = 1.25~R_s$, then $U = -4.0\times 10^9~J$
We can use conservation of energy to find the kinetic energy at $r = 1.25~R_s$:
$K+U = -2.0\times 10^9~J$
$K = (-2.0\times 10^9~J)-U$
$K = (-2.0\times 10^9~J)-(-4.0\times 10^9~J)$
$K = 2.0\times 10^9~J$
