Answer
$7.82\ km/s$
Work Step by Step
It is given that the satellite is revolving around earth.Then the gravitational force exerted by earth on moon should be equal to the centripetal force;
$F_g = F_c$
$\frac{GM_em}{r}=\frac{mv^2}{r}$
$v^2 =\frac{GM_e}{r}$
$v=\sqrt \frac{GM_e}{r}$
We know that;
G is gravitational constant = $6.67\times 10^{-11} N.m^2/kg^2$
$M_e$ is the mass of earth =$5.98\times 10^{24}\ kg$
$r =r_e\ (radius\ of\ earth) + h(altitude\ above\ earth) $
Substituting these values in the formula above:
$v =\sqrt \frac{(6.67\times 10^{-11})(5.98\times 10^{24})}{(6.37\times 10^{6}+0.160\times 10^{6})}$
$v =7.82\times 10^{3}\ m/s$
$v =7.82\ km/s$
