Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 381: 31c

Answer

The escape speed on Mars is $~~5.0~m/s$

Work Step by Step

We can find the radius of Mars: $R = \frac{6.9\times 10^3~km}{2} = 3.45\times 10^3~km$ We can find the mass of Mars: $M = (0.11)(5.98\times 10^{24}~kg) = 6.58\times 10^{23}~kg$ We can find the escape speed on Mars: $v = \sqrt{\frac{2GM}{R}}$ $v = \sqrt{\frac{(2)(6.67\times 10^{-11}~N~m^2/kg^2)(6.58\times 10^{23}~kg)}{3.45\times 10^6~m}}$ $v = 5.0~m/s$ The escape speed on Mars is $~~5.0~m/s$
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