Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 381: 33b

Answer

The multiple of the energy needed to escape from Earth which gives the energy needed to escape from Jupiter is $~~28.3$

Work Step by Step

We can write a general expression for the escape speed: $v = \sqrt{\frac{2GM}{R}}$ We can write a general expression for the kinetic energy required to escape: $K = \frac{1}{2}mv^2$ $K = \frac{1}{2}m(\sqrt{\frac{2GM}{R}})^2$ $K = \frac{GMm}{R}$ We can find the ration $\frac{K_J}{K_E}$, which is the ratio of the kinetic energy required to escape from Jupiter to the kinetic energy required to escape from the Earth: $\frac{K_J}{K_E}= \frac{\frac{GM_Jm}{R_J}}{\frac{GM_Em}{R_E}}$ $\frac{K_J}{K_E}= \frac{M_J~R_E}{M_E~R_J}$ $\frac{K_J}{K_E}= \frac{(318~M_E)~(6.37\times 10^6~m)}{(M_E)~(7.15\times 10^7~m)}$ $\frac{K_J}{K_E}= 28.3$ The multiple of the energy needed to escape from Earth which gives the energy needed to escape from Jupiter is $~~28.3$
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