Answer
$a_g = 3.69~m/s^2$
Work Step by Step
We can find the radius of Mars:
$R = \frac{6.9\times 10^3~km}{2} = 3.45\times 10^3~km$
We can find the mass of Mars:
$M = (0.11)(5.98\times 10^{24}~kg) = 6.58\times 10^{23}~kg$
We can find the gravitational acceleration on Mars:
$a_g = \frac{GM}{R^2}$
$a_g = \frac{(6.67\times 10^{-11}~N~m^2/kg^2)(6.58\times 10^{23}~kg)}{(3.45\times 10^6~m)^2}$
$a_g = 3.69~m/s^2$
