Answer
$\omega = 7.3\times 10^{-5}\ rad/s$
Work Step by Step
The value of $\omega$ at the equator remains the same. This is because the earth is rotating with same angular velocity.
Therefore; $\omega =7.292\times 10^{-5}\ rad/s $.
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 10 - Rotation - Problems - Page 288: 25c
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